kewwwi@lemmy.world to Femcel MemesEnglish · 6 个月前bazongawongaslemmy.worldimagemessage-square15fedilinkarrow-up1152
arrow-up1152imagebazongawongaslemmy.worldkewwwi@lemmy.world to Femcel MemesEnglish · 6 个月前message-square15fedilink
minus-squareolsonexi@lemmy.worldlinkfedilinkEnglisharrow-up1·26 天前a = 1.05 c = 5.2 d = 7.9 r_1 = 1 r_2 = 0.08 h = -6.7 j = 2.5 k = 8 f(y) = cosh(0.5y) (hidden) (f(t)cos(a) - t*sin(a) - d, f(t)sin(a) + t*cos(a)); -c <= t <= 2π (-(f(t)cos(a) - t*sin(a) - d), f(t)sin(a) + t*cos(a)); -c <= t <= 2π (x - h)^2 + (y - j)^2 = r_1^2 (x + h)^2 + (y - j)^2 = r_1^2 (x + h - r_1/k)^2 + (y - j + r_1/k)^2 <= r_2^2 (x - h + r_1/k)^2 + (y - j + r_1/k)^2 <= r_2^2
a = 1.05
c = 5.2
d = 7.9
r_1 = 1
r_2 = 0.08
h = -6.7
j = 2.5
k = 8
f(y) = cosh(0.5y) (hidden)
(f(t)cos(a) - t*sin(a) - d, f(t)sin(a) + t*cos(a)); -c <= t <= 2π
(-(f(t)cos(a) - t*sin(a) - d), f(t)sin(a) + t*cos(a)); -c <= t <= 2π
(x - h)^2 + (y - j)^2 = r_1^2
(x + h)^2 + (y - j)^2 = r_1^2
(x + h - r_1/k)^2 + (y - j + r_1/k)^2 <= r_2^2
(x - h + r_1/k)^2 + (y - j + r_1/k)^2 <= r_2^2