theFibonacciEffect@feddit.de to 196 · 1 year agoLeibnitz Integral [rule]feddit.deimagemessage-square3fedilinkarrow-up178
arrow-up178imageLeibnitz Integral [rule]feddit.detheFibonacciEffect@feddit.de to 196 · 1 year agomessage-square3fedilink
minus-squarelgstarn@kbin.sociallinkfedilinkarrow-up2·1 year agoFor number 4 (or maybe a new number), if a(x) and b(x) are constant, the derivatives d/dx a(x) and d/dx b(x) are zero, so all that is left is that d/dx becomes a partial derivative and can move inside the integral.
For number 4 (or maybe a new number), if a(x) and b(x) are constant, the derivatives d/dx a(x) and d/dx b(x) are zero, so all that is left is that d/dx becomes a partial derivative and can move inside the integral.