Day 7: Bridge Repair
Megathread guidelines
- Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
- You can send code in code blocks by using three backticks, the code, and then three backticks or use something such as https://topaz.github.io/paste/ if you prefer sending it through a URL
FAQ
- What is this?: Here is a post with a large amount of details: https://programming.dev/post/6637268
- Where do I participate?: https://adventofcode.com/
- Is there a leaderboard for the community?: We have a programming.dev leaderboard with the info on how to join in this post: https://programming.dev/post/6631465
Made a couple of attempts to munge the input data into some kind of binary search tree, lost some time to that, then threw my hands into the air and did a more naïve sort-of breadth-first search instead. Which turned out to be better for part 2 anyway.
Also, maths. Runs in just over a hundred milliseconds when using
AsParallel
, around half a second without.C#
List<(long, int[])> data = new List<(long, int[])>(); public void Input(IEnumerable<string> lines) { foreach (var line in lines) { var parts = line.Split(':', StringSplitOptions.TrimEntries); data.Add((long.Parse(parts.First()), parts.Last().Split(' ').Select(int.Parse).ToArray())); } } public void Part1() { var correct = data.Where(kv => CalcPart(kv.Item1, kv.Item2)).Select(kv => kv.Item1).Sum(); Console.WriteLine($"Correct: {correct}"); } public void Part2() { var correct = data.AsParallel().Where(kv => CalcPart2(kv.Item1, kv.Item2)).Select(kv => kv.Item1).Sum(); Console.WriteLine($"Correct: {correct}"); } public bool CalcPart(long res, Span<int> num, long carried = 0) { var next = num[0]; if (num.Length == 1) return res == carried + next || res == carried * next; return CalcPart(res, num.Slice(1), carried + next) || CalcPart(res, num.Slice(1), carried * next); } public bool CalcPart2(long res, Span<int> num, long carried = 0) { var next = num[0]; // Get the 10 logarithm for the next number, expand the carried value by 10^<next 10log + 1>, add the two together // For 123 || 45 // 45 ⇒ 10log(45) + 1 == 2 // 123 * 10^2 + 45 == 12345 long combined = carried * (long)Math.Pow(10, Math.Floor(Math.Log10(next) + 1)) + next; if (num.Length == 1) return res == carried + next || res == carried * next || res == combined; return CalcPart2(res, num.Slice(1), carried + next) || CalcPart2(res, num.Slice(1), carried * next) || CalcPart2(res, num.Slice(1), combined); }
you meant depth first, right? since you’re using recursion
That is true, I’ve evidently not had enough coffee yet this morning.