• ch00f@lemmy.world
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    6 months ago

    https://www.wolframalpha.com/input?i=(specific+heat+of+water)*12.8K*(1+gallon+*+water+density)

    200kjoules of heat must be removed from a gallon of water to cool from 55F to 32F (out of the ground down to pleasant drinking temperature).

    Assuming a COP of 2 for your compressor (conservative), that’s 100kjoules or 1/36 of a kWh.

    High price for a kWh of electricity is $0.25 in the US. So for your $2 subscription, you can pay for 8kWh per month or enough to cool 288 gallons of water or roughly 9 gallons per day. More than anybody would rightly use.

    What a fucking ripoff.

    • TheDezzick@lemm.ee
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      6 months ago

      Not to mention that, in a place like a public park, 55F water is totally fine. It isn’t the coolest most refreshing drink of all time but it’s damn good from a public fountain on a 90F day.