Sjmarf to Memes@lemmy.ml • 8 months agoHehsh.itjust.worksimagemessage-square45fedilinkarrow-up1813 cross-posted to: mathmemesscience_memes@mander.xyz
arrow-up1813imageHehsh.itjust.worksSjmarf to Memes@lemmy.ml • 8 months agomessage-square45fedilink cross-posted to: mathmemesscience_memes@mander.xyz
minus-squareLimitless_screaminglinkfedilink4•8 months agoIn this case yes, but if q1 was -20μC, q2 was 30μC, and r was 0.5m, then using -20μC as it is would make F equal to -21.6N which is just 21.6N of attraction force between the two charges.
minus-squarePelicanenlinkfedilink5•8 months agoIf they are oppositely charged particles, I would expect that there is a force of attraction acting on them, yes.
minus-squareLimitless_screaminglinkfedilink1•8 months agoI am not saying that’s wrong, just that there’s 21.6N of attraction force between the two charges not -21.6N.
minus-square@Bene7rddso@feddit.delinkfedilink3•8 months agoNo, if the force is negative it acts in the opposite direction
minus-squarePelicanenlinkfedilink5•8 months agoYes, and a force acting in the opposite direction of the distance is an attractive force.
In this case yes, but if q1 was -20μC, q2 was 30μC, and r was 0.5m, then using -20μC as it is would make F equal to -21.6N which is just 21.6N of attraction force between the two charges.
If they are oppositely charged particles, I would expect that there is a force of attraction acting on them, yes.
I am not saying that’s wrong, just that there’s 21.6N of attraction force between the two charges not -21.6N.
But those are the same thing.
No, if the force is negative it acts in the opposite direction
Yes, and a force acting in the opposite direction of the distance is an attractive force.