• GreyBeard@lemmy.one
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    29 days ago

    For those of you who were confused even after reading the comments: (a)(b) basically means a*b. My mind just didn’t connect that to the fact that (x-x)=0. in the (a-x)(b-x) stuff is also (x-x) which = 0, and anything * 0 = 0, so no matter the value of literally everything else in the equation, it all equals out to 0 because every single () will get multiplied by (x-x), which is 0. There, hopefully that will clear it up for anyone remaining lost. And like all good jokes, they are always best when you have to explain them.

      • superkret@feddit.org
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        28 days ago

        To make sure what’s inside the brackets is resolved internally before they’re multiplied with each other.

         (a)  (b)   =   a * b  
        (a+1)(b+1) =/= a+1*b+1
        
        • brbposting@sh.itjust.works
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          27 days ago

          TIL this notation makes it math the text up

          (a)  (b)   =   a * b  
              (a+1)(b+1) =/= a+1*b+1
          

          Edit: hmm, already shows in a code block so adding backticks didn’t do anything

      • GreyBeard@lemmy.one
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        27 days ago

        To expand on what superkret said, in math there is the concept of “order of operations”. That is to say, every function in math (add, multiply, divide) has to be done in a specific order. Since multiplication comes before addition and subtraction, if you have a formula like a-x*b-x, you will do x*b first, then a minus the result of x*b, which would give a very different result than if you did a-x and multiplied that by b-x. This is where the parenthesis come in. You are basically saying, resolve every section in parenthesis first using the proper order, then resolve the rest.

        My original example (a)(b) was over simplified, because there is no conflict there. You can also do things like (a*x)-(b*x). If there is no operator though, it is assumed multiplication, and I’m unsure why that is.

        • starman2112@sh.itjust.works
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          27 days ago

          Putting multiple asterisks in a comment makes it look italicized, at least on some Lemmy clients. If you want to have asterisks with *unitalicized* text, you gotta put a \ behind the * to negate the change

        • (a)(b) basically means a*b.

          Actually it’s (axb), since a(b+c)=(ab+ac). This is where a lot of people go wrong in the order of operations questions you see on socials - removing the brackets too soon. 1/ab=1/(axb) NOT 1/axb. If a=2 and b=3 then 1/ab=1/(2x3)=1/6, but 1/axb=1/2x3=3/2. Note that this also means it gets solved in the Brackets step of order of operations, NOT the “Multiplication” step (another common mistake).

          If there is no operator though, it is assumed multiplication

          It’s not “multiplication”, it’s a Product, a single number written as a product of factors. If a=2 and b=3 then ab is 6 written as the product of 2 and 3. ab=(2)(3)=(2x3)=6. axb=ab, 2x3=6, axb=2x3, ab=6.

          “I’m unsure why that is.”

          To show it’s a single number, not 2 separate numbers to be multiplied. Think of things like F=ma. You have to show that ma is a single number (equal to the Force), not 2 separate numbers multiplied., mxa. If you were doing something like dividing by the Force, then you have to have 1/ma=1/(mxa), NOT 1/mxa.

      • Jyek@sh.itjust.works
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        27 days ago

        Because you wrote a lot less when writing it this way. Groups of terms beside each other are multiplying each other and you have to solve what’s inside of those groups before multiplying them together.

        • Groups of terms beside each other are multiplying each other

          Actually the whole thing is a single Term. Terms are separated by operators and joined by grouping symbols, and there’s no operators between the successive brackets.

          you have to solve what’s inside of those groups before multiplying them together

          You don’t have to, but it sure makes the working-out a lot easier if you do!

          If a=1, b=2, c=3, d=4, then…

          (a+b)(c+d)=(ac+ad+bc+bd)

          (1+2)(3+4)=(1x3+1x4+2x3+2x4)=(3+4+6+8)=21

          whereas…

          (1+2)(3+4)=(3)(7)=(3x7)=21 :-)

  • Saganaki@lemmy.one
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    29 days ago

    For those that struggled like me…

    Going from a-z, write out the last three multiplicands.

      • sem
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        20 days ago

        For those of you who still struggled like me, a multiplicand in this case refers to one of the (n-x) terms.

        • a multiplicand in this case refers to one of the (n-x) terms

          Well, that’s what was apparently meant, but in fact the correct terminology here is factors. There’s only multiplicands (and multipliers) with an explicit multiplication sign. axb - multiplicand a and multiplier b, ab - Term with factors a and b, and a is the coefficient of this Term.

    • sem
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      20 days ago

      deleted by creator

  • the_tab_key@lemmy.world
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    28 days ago

    Even if the x-x term didn’t exist, the equation is already simplified (fully factored) so there is nothing to do anyway.

    • is already simplified (fully factored)

      No it isn’t, given one of the factors is equal to zero. That’s like saying 2/4 is fully simplified when clearly it isn’t. Students lose marks in tests for not simplifying their answers. Writing 2/4 as an answer would only get half-marks. Similarly, the only full-marks answer to this question is 0.

      • the_tab_key@lemmy.world
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        17 days ago

        My stipulation was that the x-x term didn’t exist, such that the equation would be fully simplified (assuming the request was “factor and simplify”). Yes, you could also “expand and simplify” (as in your other comment) but I would argue the result of that would be less simplified than the factored version. Eye of the beholder type thing.

        I agree that if x-x did exist as a term then expand and simplify would be correct (that is if x-x wasn’t noticed to be 0 immediately and no expansion would be needed at all).

        • My stipulation was that the x-x term didn’t exist, such that the equation would be fully simplified

          And it STILL wouldn’t be simplified.

          “factor and simplify”

          Factorising is the opposite process to expanding, so no, there’s no such thing as “factor and simplify”.

          I would argue the result of that would be less simplified than the factored version. Eye of the beholder type thing.

          It’s a definition of Maths thing. Simplified answers don’t have brackets in them.

          • the_tab_key@lemmy.world
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            16 days ago

            Are you a high school math teacher by chance? Because you’re using a rigid definition of simplify that I don’t necessarily agree with. For example, if I give you the fraction:

            (x2+(a+b)x+ab)/(x2+ax-bx-ab)

            And told you to simplify, what would you do?

            • Are you a high school math teacher by chance?

              Yep.

              Because you’re using a rigid definition of simplify that I don’t necessarily agree with.

              You don’t agree with Maths textbooks? 😂

              “And told you to simplify, what would you do?” - I would ask you what on Earth it’s supposed to say, given it’s formatted all weird! 😂

              • the_tab_key@lemmy.world
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                16 days ago

                It’s raw text on my side, looks fine. It might be fixed now? Not sure how the formatting works for equations on Lemmy.

                And correct, I don’t agree with whatever you are interpreting from your math textbooks because “simplify” literally means to make the equation easier to understand. You are arguing that “expand and simplify” is the exact same thing as “simplify”… Which if they were, it would just be in word, wouldn’t it… Sometimes factoring is prudent. Other times expansion is necessary. This is exemplified by the math I gave in the previous comment.

                And thanks for the downvotes. I hope you don’t treat your students the same way when they question your ultimate wisdom by dismissing them outright. I certainly don’t to mine.

                • “simplify” literally means to make the equation easier to understand

                  Nope. It means to present it in the simplest way possible. e.g. 5/10=1/2.

                  You are arguing that “expand and simplify” is the exact same thing as “simplify”

                  No I’m not. I’m saying “expand and simplify” is a thing in all high school Maths textbooks, “factor and simplify” isn’t a thing in any of them.

                  “Sometimes factoring is prudent” - if you’re trying to solve an equation, yes, but solving and simplifying aren’t the same thing. If I arrive at an answer of 5/10 then I have solved but not simplified. Sometimes it’s not even possible to simplify, because the answer is already in the simplest form possible, such as an answer of 1/2. I teach students when to recognise when something can be simplified and when it can’t. Your original contention was that the Term was already simplified, and it wasn’t.

                  “And thanks for the downvotes.” - I downvote anything that is incorrect, just like a student would lose marks for same.

    • sem
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      20 days ago

      What’s the right term then? “Multiplied through?” ? “Complicated?”

  • LostXOR@fedia.io
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    28 days ago

    Fun fact, omitting the (x-x) zero term and expanding the entire polynomial, you’d get something with 2^25 = 33,554,432 terms. May be slightly excessive!

      • copd@lemmy.world
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        28 days ago

        Technically there is a (x - 𝑥) in there. U+1D465 != x so this post is a little meh

        • MBM@lemmings.world
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          28 days ago

          Mathematicians do weird stuff to get more letters, but I’ve never seen anyone use x and 𝑥 for different things

          • threelonmusketeers@sh.itjust.works
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            27 days ago

            I’ve never seen anyone use x and 𝑥 for different things

            Yeah, me neither. I have had situations where I needed to distinguish between u, v, nu, and upsilon though. I had to be very careful with my handwriting that day…

          • joshthewaster@lemmy.world
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            28 days ago

            They also wouldn’t want to be ambiguous. If I was trying to write this problem the a, b, c… would get replaced by something like a_1, a_2,…, a_26 to be clearer. This problem works as a fun gotcha but isn’t something that would come up in the real world.

        • pyre@lemmy.world
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          26 days ago

          the first variables aren’t roman. they’re italicized as well. idk where you’re getting the x vs x thing.

        • sem
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          20 days ago

          Do do, do do do do do…

      • shastaxc@lemm.ee
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        27 days ago

        Assuming both x represent the same number. There’s no reason to assume the ellipses should include x-x. Why would alphabetic order be involved at all?

        • pyre@lemmy.world
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          27 days ago

          have you never taken math? I’m seriously asking because you’re incredibly wrong in both statements.

            • nyctre@lemmy.world
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              27 days ago

              So your argument is that in the list “a, b, c, …, z” the “…” Bit could be anything and we have no way of knowing what’s there and therefore the problem is unsolvable? Or what are you saying exactly?

              • shastaxc@lemm.ee
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                27 days ago

                Yes. The variables a, b, c, and z must have a stated correlation. Variable names do not implicitly have any relation between them. Ellipses work for numbers because a series of 1, 2, 3 … 100 can be inferred using the rules of mathematics. A series of a, b, c … z cannot; the series can only be inferred using the rules of the English language.

                • pyre@lemmy.world
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                  26 days ago

                  so is the word “simplify”. I guess we’ll never know what they mean by that because if you pretend you don’t speak English, then there’s no way of knowing!

                • The variables a, b, c, and z must have a stated correlation

                  They do! a is the pronumeral in the 1st factor, b is the pronumeral in the 2nd factor, c is the pronumeral in the 3rd factor - i.e. the first 3 terms in a sequence - and the nth factor has the pronumeral z, and you think that ISN’T stating a relationship between term t of the sequence and the t-th pronumeral? 😂

                  “the series can only be inferred using the rules of the English language” - well, they haven’t used Greek letters for it, have they?? 😂

                • nyctre@lemmy.world
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                  27 days ago

                  Right. Well, yeah, I guess your pedantic response is a lot more logical than the intended answer that other people have pointed out. Have a nice day!